Exemp Dozza (1)
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Exemp Dozza (1)

by litim said

‫ﺃ‬ ‫ﻗﻮﻱ‬ ‫ﺃﺳﺎﺱ‬ ‫ﺑﻮﺍﺳﻄﺔ‬ ‫ﺿﻌﻴﻒ‬ ‫ﲪﺾ‬ ‫ﻣﻌﺎﻳﺮﺓ‬ : ) HCOOH ‫ﻣﻊ‬ NaOH ( . ** ‫ﺍﻟﺘﺠﺮﺑﺔ‬ : ( ) / 3,8 pKa HCOOH HCOO − = ‫ﺍﳌﻴﺜﺎﻧﻮﻳﻚ‬ ‫ﲪﺾ‬ ‫ﳏﻠﻮﻝ‬ ‫ﺑﻴﺸﺮ‬ ‫ﰲ‬ ‫ﻧﻀﻊ‬ { } 20 , : a a V mL C HCOOH = ‫ﺣﺠﻢ‬ ‫ﺗﺪﺭﳛﻴﺎ‬ ‫ﻋﻠﻴﻪ‬ ‫ﻧﺴﻜﺐ‬ ‫ﻭ‬ b V ‫ﺃﺳﺎﺱ‬ ‫ﳏﻠﻮﻝ‬ ‫ﻣﻦ‬ { } 1 , 0,2 : b... More

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