sistema ciclico 2
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sistema ciclico 2

by Aldana

• 30°= ?rad 360° = 2 πrad 30° x 360°x = 30° (2 πrad) X = 30° (2πrad) = πrad 360° 6 • 60° = ?rad 360° = 2 πrad 360x = 60° (2 πrad) X = 60° (2 πrad) = πrad = 1. 047197551 360 3 • 1rad 360° = 2 πrad X 1rad X = 360° (1rad) = 180° = 57°-17’-44” 2 πrad π

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